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parsing through json without using key value python

RM answered on September 24, 2020 Popularity 5/10 Helpfulness 1/10

answer parsing through json without using key value python

parsing through json without using key value python

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data = [
  {
    "id": 1,
    "name": "Leanne Graham",
    "username": "Bret",
    "email": "Sincere@april.biz",
    "address": {
      "street": "Kulas Light",
      "suite": "Apt. 556",
      "city": "Gwenborough",
      "zipcode": "92998-3874",
      "geo": {
        "lat": "-37.3159",
        "lng": "81.1496"
      }
    },
    "phone": "1-770-736-8031 x56442",
    "website": "hildegard.org",
    "company": {
      "name": "Romaguera-Crona",
      "catchPhrase": "Multi-layered client-server neural-net",
      "bs": "harness real-time e-markets"
    },
    "other": ["This", "is", "a list"]
  },
  {
    "id": 2,
    "name": "Ervin Howell",
    "username": "Antonette",
    "email": "Shanna@melissa.tv",
    "address": {
      "street": "Victor Plains",
      "suite": "Suite 879",
      "city": "Wisokyburgh",
      "zipcode": "90566-7771",
      "geo": {
        "lat": "-43.9509",
        "lng": "-34.4618"
      }
    },
    "phone": "010-692-6593 x09125",
    "website": "anastasia.net",
    "company": {
      "name": "Deckow-Crist",
      "catchPhrase": "Proactive didactic contingency",
      "bs": "synergize scalable supply-chains"
    },
    "other": ["This", "is", "another list"]
  },
]    

def show_indices(obj, indices):
    for k, v in obj.items() if isinstance(obj, dict) else enumerate(obj):
        if isinstance(v, (dict, list)):
            yield from show_indices(v, indices + [k])
        else:
            yield indices + [k], v

for keys, v in show_indices(data, []):
    print(keys, v)

Popularity 5/10 Helpfulness 1/10 Language javascript

Source: stackoverflow.com

Tags: javascript json key-value parsing python using

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Contributed on Sep 24 2020

0 Answers Avg Quality 2/10

parsing through json without using key value python

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