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django admin action

Better Bird answered on March 24, 2021 Popularity 10/10 Helpfulness 6/10

answer django admin action

related django admin action

django admin action

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from django.contrib import admin
from myapp.models import Article

def make_published(modeladmin, request, queryset):
    queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"

class ArticleAdmin(admin.ModelAdmin):
    list_display = ['title', 'status']
    ordering = ['title']
    actions = [make_published]

admin.site.register(Article, ArticleAdmin)

Popularity 10/10 Helpfulness 6/10 Language python

Source: Grepper

Tags: action django-admin python

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Contributed on Mar 24 2021

Better Bird

0 Answers Avg Quality 2/10

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django admin action

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# Add this code to admin.py
#example : Published Article
def make_published(modeladmin, request, queryset):
    queryset.update(status='p')
make_published.short_description = "Mark selected stories as published"

Popularity 10/10 Helpfulness 3/10 Language python

Source: Grepper

Tags: action ac

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Contributed on Mar 24 2021

Better Bird

0 Answers Avg Quality 2/10

django admin action

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django admin action

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django admin action

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