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lodash groupby return array

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Zany Zebra answered on May 25, 2021 Popularity 10/10 Helpfulness 2/10

answer lodash groupby return array

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lodash groupby return array

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export const groupArrayBy = (arr, groupBy) => {

    let newArr = []
    arr.map((item) => {
        if(item[groupBy]) {
            let finded = newArr.filter((newItem) => newItem[groupBy] === item[groupBy])
            if(finded.length > 0) {
                finded[0].products.push(item)
            } else {
                newArr.push({category: item[groupBy], products: [item]})
            }
        }
    })

    return newArr
}

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: group-by javascript lodash return

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Contributed on May 25 2021

Zany Zebra

0 Answers Avg Quality 2/10

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lodash groupBy

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Creates an object composed of keys generated from the results of running 
each element of collection thru iteratee. The order of grouped values is 
determined by the order they occur in collection. The corresponding value 
of each key is an array of elements responsible for generating the key. 
The iteratee is invoked with one argument: (value).

_.groupBy([6.1, 4.2, 6.3], Math.floor);
// => { '4': [4.2], '6': [6.1, 6.3] }
 
// The `_.property` iteratee shorthand.
_.groupBy(['one', 'two', 'three'], 'length');
// => { '3': ['one', 'two'], '5': ['three'] }

Popularity 10/10 Helpfulness 3/10 Language javascript

Source: lodash.com

Tags: group-by group-b

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Contributed on May 10 2022

deadman

0 Answers Avg Quality 2/10

lodash groupby with map

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var result = _.chain(mockData)
      .groupBy(function(item) {
        return moment(item.start_date.substring(0,10)).format("MMM-DD-YYYY"); 
      })
      .map((value, key) => {
        return {
          date: key, 
          param: value
        }
      })
      .value();

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Source: stackoverflow.com

Tags: group-by group-b

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Contributed on Oct 27 2022

Ivan Oboth

0 Answers Avg Quality 2/10

lodash groupby return array

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-1

   let arr = [{
	"birthdate": "1993",
	"name": "Ben"
},
{
	"birthdate": "1994",
	"name": "John"
},
{
	"birthdate": "1995",
	"name": "Larry"
},
{
	"birthdate": "1995",
	"name": "Nicole"
},
{
	"birthdate": "1996",
	"name": "Jane"
},
{
	"birthdate": "1996",
	"name": "Janet"
},
{
	"birthdate": "1996",
	"name": "Dora"
},
];

const res = arr.reduce((ac, a) => {
let temp = ac.find(x => x.birthdate === a.birthdate);
if (!temp) ac.push({ ...a,
	name: [a.name]
})
else temp.name.push(a.name)
return ac;
}, [])
console.log(res);

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: stackoverflow.com

Tags: group-by group-b

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Contributed on May 25 2021

Zany Zebra

0 Answers Avg Quality 2/10

lodash groupby return array

Comment

-1

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.5/lodash.min.js"></script>

Popularity 10/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: group-by group-b

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Contributed on May 25 2021

Zany Zebra

0 Answers Avg Quality 2/10

lodash groupby return array

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