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counting sort using malloc and size-t type c

Innocent Ibex answered on October 11, 2021 Popularity 1/10 Helpfulness 1/10

answer counting sort using malloc and size-t type c

counting sort using malloc and size-t type c

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#include <stdio.h>
#include <stdlib.h>

void counting_sort_mm(int *array, int n, int min, int max)
{
  int i, j, z;

  int range = max - min + 1;
  int *count = malloc(range * sizeof(*array));

  for(i = 0; i < range; i++) count[i] = 0;
  for(i = 0; i < n; i++) count[ array[i] - min ]++;

  for(i = min, z = 0; i <= max; i++) 
  {
    for(j = 0; j < count[i - min]; j++) 
    {
      array[z++] = i;
    }
  } 

  free(count);
}

void counting_sort(int *array, int n)
{
  int i, min, max;

  min = max = array[0];
  for(i=1; i < n; i++) 
  {
    if ( array[i] < min ) 
    {
      min = array[i];
    } else if ( array[i] > max ) 
    {
      max = array[i];
    }
  }
}

Popularity 1/10 Helpfulness 1/10 Language c

Source: stackoverflow.com

Tags: c counting-sort malloc size-t using

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