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find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

Pleasant Pintail answered on December 3, 2021 Popularity 3/10 Helpfulness 4/10

answer find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

Comment

function asc(arr) {
    let map = new Map
    let c = 1;
    for (let i = 0; i < arr.length; i++) {
        if (map.has(arr[i])) {
            map.set(arr[i], map.get(arr[i]) + 1)
        }
        else {
            map.set(arr[i], c)
        }
    }
    let narr = [...map];
    let tmp;
    for (i = 0; i < narr.length; i++) {
        for (j = i + 1; j < narr.length; j++) {
            if (narr[i][1] > narr[j][1]) {
                tmp = narr[i];
                narr[i] = narr[j];
                narr[j] = tmp;
            }
            else if ((narr[i][1] = narr[j][1])) {
                if (narr[i][0] > narr[j][0]) {
                    tmp = narr[i];
                    narr[i] = narr[j];
                    narr[j] = tmp;
                }
            }
        }
    }
    return narr;
}
arr = [3, 8, 7, 4, 7, 3, 4];
console.log(asc(arr));

Popularity 3/10 Helpfulness 4/10 Language typescript

Source: stackoverflow.com

Tags: character each find numbers typescript

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Contributed on Dec 03 2021

Pleasant Pintail

0 Answers Avg Quality 2/10

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find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

Comment

function sortByOccurences(arr) {
    // create a new map
    let map = new Map();
    let count = 1;
    let len = arr.length;
    // set the element and count in map
    for (let i = 0; i < len; i++) {
        // if map have this element then count + 1
        if (map.has(arr[i])) {
            map.set(arr[i], map.get(arr[i]) + 1)
        }
        // else set the count as 1
        else {
            map.set(arr[i], count)
        }
    }
    // assign the map as 2D array
    let newArray = [...map];
    //sort the elements in decending order
    newArray.sort((a, b) => (b[0] - a[0]))
    //sort the occurence in decending order
    newArray.sort((a, b) => (b[1] - a[1]))
    let result = newArray.map(x => x[0])
    return result;
}

let arr = [3, 3, 4, 4, 7, 8]
console.log(sortByOccurences(arr));

Popularity 1/10 Helpfulness 1/10 Language whatever

Source: Grepper

Tags: each character numbers whatever find

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Contributed on Apr 03 2022

Achyuta Pradhan

0 Answers Avg Quality 2/10

find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

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find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

Closely Related Answers

find the number of occurences of each character and print it in the decreasing order of occurences, if 2 or more number occurs the same number of times, print the numbers in decreasing order.

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