Breaking News: Grepper is joining You.com. Read the official announcement!
Check it out

function nbYear(p0, percent, aug, p) { let n = 0; while(p0 < p) { p0 = p0 + Math.round(p0 * (percent/100)) + aug; n ++; } return n; }

Add Answer
marwa kilani answered on April 27, 2022 Popularity 1/10 Helpfulness 1/10

Contents

  • answer function nbYear(p0, percent, aug, p) { let n = 0; while(p0 < p) { p0 = p0 + Math.round(p0 * (percent/100)) + aug; n ++; } return n; }

    • More Related Answers

  • find percentile with respect to sigma numpy
  • Debug this def Total(math, computer, english): return math + computer + english def Average(total, n): return total / n def Result(total, y): average = Average(total, 3) if average >= y: return "Pass" else: return "F

    • function nbYear(p0, percent, aug, p) { let n = 0; while(p0 < p) { p0 = p0 + Math.round(p0 * (percent/100)) + aug; n ++; } return n; }

    Comment
    0
    Popularity 1/10 Helpfulness 1/10 Language python
    Source: Grepper
    Tags: function let n python return
    Link to this answer
    Share Copy Link
    marwa kilani
    Contributed on Apr 27 2022
    marwa kilani
    0 Answers  Avg Quality 2/10

    X

    Continue with Google

    By continuing, I agree that I have read and agree to Greppers's Terms of Service and Privacy Policy.
    X
    Grepper Account Login Required

    Oops, You will need to install Grepper and log-in to perform this action.