Breaking News: Grepper is joining You.com. Read the official announcement!

pointers

Felipe Cravero answered on June 20, 2021 Popularity 9/10 Helpfulness 2/10

answer pointers

related pointer

pointers

Comment

// C++ program to demonstrate use of * for pointers in C++
#include <iostream>
using namespace std;
 
int main()
{
    // A normal integer variable
    int Var = 10;
 
    // A pointer variable that holds address of var.
    int *ptr = &Var;
 
    // This line prints value at address stored in ptr.
    // Value stored is value of variable "var"
    cout << "Value of Var = "<< *ptr << endl;
 
    // The output of this line may be different in different
    // runs even on same machine.
    cout << "Address of Var = " <<  ptr << endl;
 
    // We can also use ptr as lvalue (Left hand
    // side of assignment)
    *ptr = 20; // Value at address is now 20
 
    // This prints 20
    cout << "After doing *ptr = 20, *ptr is "<< *ptr << endl;
 
    return 0;
}
 
// This code is contributed by
// shubhamsingh10

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: www.geeksforgeeks.org

Tags: c++ pointers

Link to this answer
Share Copy Link

Contributed on Jul 02 2022

Felipe Cravero

0 Answers Avg Quality 2/10

Closely Related Answers

pointer

Comment

#include <iostream>
// by using increment sign we know whole array
int main()
{
	using namespace std;
	int ar[] = { 1,2,3,4,5,6,7,8,9,10 };
	for (int m : ar)
	{
		cout << m << endl;
	}
	return 0;
}

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: www.codesdope.com

Tags: c++

Link to this answer
Share Copy Link

Contributed on Jun 20 2021

Unusual Unicorn

0 Answers Avg Quality 2/10

pointer

Comment

As discussed earlier, 'p' is a pointer to 'a'. Since 'a' has a value of 10, so '*p' is 10. 'p' stores the address of a. So the output p = 0xffff377c implies that 0xffff377c is the address of 'a'. '&p' represents the address of 'p' which is 0xffff3778. Now, '*&p' is the value of '&p' and the value of '&p' is the address of 'a'. So, it is 0xffff377c.

Popularity 9/10 Helpfulness 2/10 Language cpp

Source: www.codesdope.com

Tags: c++

Link to this answer
Share Copy Link

Contributed on Jun 20 2021

Unusual Unicorn

0 Answers Avg Quality 2/10

pointer

Comment

p = 0xffff377c
*p = 10
&p = 0xffff3778
*&p = 0xffff377c

Popularity 9/10 Helpfulness 1/10 Language cpp

Source: www.codesdope.com

Tags: c++

Link to this answer
Share Copy Link

Contributed on Jun 20 2021

Unusual Unicorn

0 Answers Avg Quality 2/10

pointer

Comment

#include <iostream>
using namespace std;
int main()
{
	int* p;
	p = new int;
	if (p)
	{
		cout << "success";
	}
	return 0;
}

Popularity 8/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: c++

Link to this answer
Share Copy Link

Contributed on Mar 18 2022

Info Important

0 Answers Avg Quality 2/10

pointer

Comment

/*Chrome*/
@media screen and (-webkit-min-device-pixel-ratio:0) {
    input[type='range'] {
      overflow: hidden;
      width: 80px;
      -webkit-appearance: none;
      background-color: #9a905d;
    }
    
    input[type='range']::-webkit-slider-runnable-track {
      height: 10px;
      -webkit-appearance: none;
      color: #13bba4;
      margin-top: -1px;
    }
    
    input[type='range']::-webkit-slider-thumb {
      width: 10px;
      -webkit-appearance: none;
      height: 10px;
      cursor: pointer;
      background: #434343;
      box-shadow: -80px 0 0 80px #43e5f7;
    }

}
/** FF*/
input[type="range"]::-moz-range-progress {
  background-color: #43e5f7; 
}
input[type="range"]::-moz-range-track {  
  background-color: #9a905d;
}
/* IE*/
input[type="range"]::-ms-fill-lower {
  background-color: #43e5f7; 
}
input[type="range"]::-ms-fill-upper {  
  background-color: #9a905d;
}

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: whatever

Link to this answer
Share Copy Link

Contributed on Aug 25 2022

Poised Piranha

0 Answers Avg Quality 2/10

pointer

Comment

#include <stdio.h>

int main () {

   int  var1;
   char var2[10];

   printf("Address of var1 variable: %x\n", &var1  );
   printf("Address of var2 variable: %x\n", &var2  );

   return 0;
}

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: www.tutorialspoint.com

Tags: whatever

Link to this answer
Share Copy Link

Contributed on Sep 19 2022

Super Salmon

0 Answers Avg Quality 2/10

pointers

Contents

More Related Answers

pointers

Closely Related Answers

pointer

pointer

pointer

pointer

pointer

pointer

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.