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Dark Dotterel answered on March 5, 2020 Popularity 10/10 Helpfulness 4/10

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ages = [5, 12, 17, 18, 24, 32]
adults = list(filter(lambda x: x >= 18, ages))

print(adults)
# [18, 24, 32]

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: filter python

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Contributed on Aug 14 2022

Dark Dotterel

0 Answers Avg Quality 2/10

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python filter

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number_list = range(-5, 5)
less_than_zero = list(filter(lambda x: x < 0, number_list))
print(less_than_zero)

# Output: [-5, -4, -3, -2, -1]

Popularity 10/10 Helpfulness 5/10 Language python

Source: book.pythontips.com

Tags: filter fi

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Contributed on Mar 05 2020

Relieved Rook

0 Answers Avg Quality 2/10

filter python

Comment

## filter(boolean_func, list)

items = [1, 2, 3, 4]
list(filter(lambda x: (x%2 != 0), items)) ## [1, 3]

Popularity 8/10 Helpfulness 5/10 Language python

Source: Grepper

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Contributed on Feb 14 2024

Innocent Iguana

0 Answers Avg Quality 2/10

python filter

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lst = [1,2,3,4,5,6,7,8,9]
list(filter(lambda x:x%2 == 0, lst))

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: filter fi

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Contributed on Mar 04 2022

Gentle Gannet

0 Answers Avg Quality 2/10

filter in python

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# function filter name ==/ 'omar', 'omer', 'osama', 'ahmed', 'mahmuod', 'abdelrhman'
# and we need just name's start with 'o'

def name(n):

    return n.startswith("o")


names_list = ['omar', 'omer', 'osama', 'ahmed', 'mahmuod', 'abdelrhman']

x = filter(name, names_list)

for l in x:

    print(l)

print("#" * 100)

# function filter number ==/ 1, 20 , 38 , 550 , 3 and we need the numbers bigger than 2


def num(number):

    if number > 2.5:
        return number


num_list = [1, 20, 38, 550, 3]


my_num = filter(num, num_list)

print(list(filter(num, num_list))) # Without Loop.

for n in my_num: # With Loop.

    print(n)

print("#" * 100)

# function filter name with lambda :-

n = ['omar', 'omer', 'osama', 'ahmed', 'mahmuod', 'abdelrhman']

for p in filter(lambda name: name.startswith("a"), n):

    print(p)

print("#" * 100)

# function filter number with lambda :-

num_list = [1, 20, 38, 550, 3]

for N in filter(lambda num: num > 2.4, num_list):

    print(N)

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: filter fi

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Contributed on Aug 14 2022

Lucifer

0 Answers Avg Quality 2/10

filter in python

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"""filter() is a higher-order built-in function that takes a function and iterable as 
inputs and returns an iterator with the elements from the iterable for which the function 
returns True"""
"""The code below uses filter() to get the names in cities that are fewer than 10 
characters long to create the list short_cities"""

cities = ["New York City", "Los Angeles", "Chicago", "Mountain View", "Denver", "Boston"]

def is_short(name):
    return len(name) < 10

short_cities = list(filter(is_short, cities))
print(short_cities)

>>>['Chicago', 'Denver', 'Boston']

Popularity 10/10 Helpfulness 3/10 Language python

Source: classroom.udacity.com

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Contributed on Jul 31 2022

josh.ipynb

0 Answers Avg Quality 2/10

filter function in python

Comment

nums1 = [2,3,5,6,76,4,3,2]

def bada(num):
    return num>4 # bada(2) o/p: False, so wont return.. else anything above > value returns true hence filter function shows result  

filters = list(filter(bada, nums1))
print(filters)
 
(or) 
 
bads = list(filter(lambda x: x>4, nums1))
print(bads)

Popularity 10/10 Helpfulness 2/10 Language python

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Tags: filter fi

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Contributed on Aug 07 2020

Tired Pasha rocks

0 Answers Avg Quality 2/10

filter function in python

Comment

# filter is just filters things

my_list = [1, 2, 3, 4, 5, 6, 7]


def only_odd(item):
    return item % 2 == 1	# checks if it is odd or even


print(list(filter(only_odd, my_list)))

Popularity 10/10 Helpfulness 2/10 Language python

Source: Grepper

Tags: filter fi

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Contributed on Dec 31 2020

Tejas Naik

0 Answers Avg Quality 2/10

python filter

Comment

ages = [5, 12, 17, 18, 24, 32]
def myFunc(x):
  if x < 18:
    return False
  else:
    return True
  
adults = filter(myFunc, ages)
for x in adults:
  print(x)     		# 18 24 32

Popularity 10/10 Helpfulness 2/10 Language python

Source: websitesetup.org

Tags: filter fi

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Contributed on May 13 2021

VasteMonde

0 Answers Avg Quality 2/10

python filter

Comment

number_list = range(-5, 5)
less_than_zero = list(filter(lambda x: x < 0, number_list))
print(less_than_zero)

# Output: [-5, -4, -3, -2, -1]

Popularity 10/10 Helpfulness 2/10 Language python

Source: book.pythontips.com

Tags: python py

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Contributed on Aug 14 2021

0 Answers Avg Quality 2/10

pyton filter

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