directory that user uploads files to and mandate a predefined format for the filename with python

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@app.route('/uploads/<filename>')
@login_required
def upload(filename):
    return send_from_directory(os.path.join(
        app.config['UPLOAD_PATH'], current_user.get_id()), filename)

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Source: blog.miguelgrinberg.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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def allowed_file(filename):
    return '.' in filename and \
           filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the file part
        if 'file' not in request.files:
            flash('No file part')
            return redirect(request.url)
        file = request.files['file']
        # If the user does not select a file, the browser submits an
        # empty file without a filename.
        if file.filename == '':
            flash('No selected file')
            return redirect(request.url)
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
            return redirect(url_for('download_file', name=filename))
    return '''
    <!doctype html>
    <title>Upload new File</title>
    <h1>Upload new File</h1>
    <form method=post enctype=multipart/form-data>
      <input type=file name=file>
      <input type=submit value=Upload>
    </form>
    '''

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Source: flask.palletsprojects.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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import imghdr
import os
from flask import Flask, render_template, request, redirect, url_for, abort
from werkzeug.utils import secure_filename

app = Flask(__name__)
app.config['MAX_CONTENT_LENGTH'] = 1024 * 1024
app.config['UPLOAD_EXTENSIONS'] = ['.jpg', '.png', '.gif']
app.config['UPLOAD_PATH'] = 'uploads'

def validate_image(stream):
    header = stream.read(512)
    stream.seek(0) 
    format = imghdr.what(None, header)
    if not format:
        return None
    return '.' + (format if format != 'jpeg' else 'jpg')

@app.route('/')
def index():
    return render_template('index.html')

@app.route('/', methods=['POST'])
def upload_files():
    uploaded_file = request.files['file']
    filename = secure_filename(uploaded_file.filename)
    if filename != '':
        file_ext = os.path.splitext(filename)[1]
        if file_ext not in app.config['UPLOAD_EXTENSIONS'] or \
                file_ext != validate_image(uploaded_file.stream):
            abort(400)
        uploaded_file.save(os.path.join(app.config['UPLOAD_PATH'], filename))
    return redirect(url_for('index'))

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Source: blog.miguelgrinberg.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

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directory that user uploads files to and mandate a predefined format for the filename with python

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from flask import send_from_directory

@app.route('/uploads/<filename>')
def upload(filename):
    return send_from_directory(app.config['UPLOAD_PATH'], filename)

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Source: blog.miguelgrinberg.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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<!doctype html>
<html>
  <head>
    <title>File Upload</title>
  </head>
  <body>
    <h1>File Upload</h1>
    <form method="POST" action="" enctype="multipart/form-data">
      <p><input type="file" name="file"></p>
      <p><input type="submit" value="Submit"></p>
    </form>
    <hr>
    {% for file in files %}
      <img src="{{ url_for('upload', filename=file) }}" style="width: 64px">
    {% endfor %}
  </body>
</html>

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Source: blog.miguelgrinberg.com

Tags: python directory format

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Contributed on Sep 06 2022

Armin Alborzi

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directory that user uploads files to and mandate a predefined format for the filename with python

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<html>
  <head>
    <title>File Upload</title>
    <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.7.1/min/dropzone.min.css">
  </head>
  <body>
    <h1>File Upload</h1>
    <form action="{{ url_for('upload_files') }}" class="dropzone">
    </form>
    <script src="https://cdnjs.cloudflare.com/ajax/libs/dropzone/5.7.1/min/dropzone.min.js"></script>
  </body>
</html>

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Source: blog.miguelgrinberg.com

Tags: format python directory

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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@app.errorhandler(413)
def too_large(e):
    return "File is too large", 413

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Source: blog.miguelgrinberg.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

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directory that user uploads files to and mandate a predefined format for the filename with python

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if file_ext not in app.config['UPLOAD_EXTENSIONS'] or \
                file_ext != validate_image(uploaded_file.stream):
            return "Invalid image", 400

Popularity 1/10 Helpfulness 1/10 Language python

Source: blog.miguelgrinberg.com

Tags: format python directory

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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0

import imghdr
import os
from flask import Flask, render_template, request, redirect, url_for, abort, \
    send_from_directory
from werkzeug.utils import secure_filename

app = Flask(__name__)
app.config['MAX_CONTENT_LENGTH'] = 2 * 1024 * 1024
app.config['UPLOAD_EXTENSIONS'] = ['.jpg', '.png', '.gif']
app.config['UPLOAD_PATH'] = 'uploads'

def validate_image(stream):
    header = stream.read(512)
    stream.seek(0)
    format = imghdr.what(None, header)
    if not format:
        return None
    return '.' + (format if format != 'jpeg' else 'jpg')

@app.errorhandler(413)
def too_large(e):
    return "File is too large", 413

@app.route('/')
def index():
    files = os.listdir(app.config['UPLOAD_PATH'])
    return render_template('index.html', files=files)

@app.route('/', methods=['POST'])
def upload_files():
    uploaded_file = request.files['file']
    filename = secure_filename(uploaded_file.filename)
    if filename != '':
        file_ext = os.path.splitext(filename)[1]
        if file_ext not in app.config['UPLOAD_EXTENSIONS'] or \
                file_ext != validate_image(uploaded_file.stream):
            return "Invalid image", 400
        uploaded_file.save(os.path.join(app.config['UPLOAD_PATH'], filename))
    return '', 204

@app.route('/uploads/<filename>')
def upload(filename):
    return send_from_directory(app.config['UPLOAD_PATH'], filename)

Popularity 1/10 Helpfulness 1/10 Language python

Source: blog.miguelgrinberg.com

Tags: directory format python

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Contributed on Sep 06 2022

Armin Alborzi

0 Answers Avg Quality 2/10

directory that user uploads files to and mandate a predefined format for the filename with python

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