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Count Frequency of elements in array using python

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Thoughtless Tiger answered on December 29, 2020 Popularity 9/10 Helpfulness 2/10

answer Count Frequency of elements in array using python

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Count Frequency of elements in array using python

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def countFreq(arr):
    visited = [False for _ in range(len(arr))]
    
    for i in range(len(arr)):
        count = 1
        if visited[i]:
            continue
        for j in range(i+1, len(arr)):
            if arr[i] == arr[j]:
                count += 1
                visited[j] = True
        visited[i] = True
        print(f'{arr[i]} : {count}')

# Time complexity: O(n * n)
# space complexity: O(n)

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Contributed on Oct 25 2022

Thoughtless Tiger

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Python program to count the frequency of

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# Python program to count the frequency of
# elements in a list using a dictionary
 
def CountFrequency(my_list):
     
    # Creating an empty dictionary
    freq = {}
    for items in my_list:
        freq[items] = my_list.count(items)
#Print:     
    for key, value in freq.items():
        print ("% d : % d"%(key, value))
        
#Output: 
   1 :  5
   2 :  4
   3 :  3
   4 :  3
   5 :  2

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Source: www.geeksforgeeks.org

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Contributed on Aug 15 2022

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find frequency of numbers in list python

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from collections import Counter

def frequency_table(n):
    table = Counter(n)
    print('Number\tFrequency')
    for number in table.most_common() :
        print('{0}\t{1}'.format(number[0], number[1]))
        
# src : Doing Math With Python

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Contributed on Dec 29 2020

icy_milktea27

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Count the Frequency of Elements in a List

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def count_frequency(numbers):
    frequency = {}
    for num in numbers:
        if num in frequency:
            frequency[num] += 1
        else:
            frequency[num] = 1
    return frequency

numbers = [1, 2, 2, 3, 1, 4, 2, 4, 5]
frequency = count_frequency(numbers)
print("Frequency:", frequency)

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Contributed on Aug 14 2023

Python in LatEx :P

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Count Frequency of elements in array using python

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