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order list of dict by dict value

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Curious Cod answered on April 22, 2020 Popularity 7/10 Helpfulness 3/10

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order list of dict by dict value

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newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])

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Source: stackoverflow.com

Tags: list whatever

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Contributed on Feb 03 2023

Curious Cod

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python dict order a dict by key

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d1 = dict(sorted(d.items(), key = lambda x:x[0]))

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Source: stackoverflow.com

Tags: key

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Contributed on Oct 20 2021

Dull Donkey

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sort dict by value

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x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Source: stackoverflow.com

Tags: python py

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Contributed on Apr 22 2020

Enchanting Elephant

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sort dict by value

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dict(sorted(x.items(), key=lambda item: item[1]))

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Source: Grepper

Tags: python py

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Contributed on Mar 17 2021

Hilarious Hawk

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sort dict by value python 3

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>>> d = {"aa": 3, "bb": 4, "cc": 2, "dd": 1}
>>> for k in sorted(d, key=d.get, reverse=True):
...     k, d[k]
...
('bb', 4)
('aa', 3)
('cc', 2)
('dd', 1)

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Source: stackoverflow.com

Tags: python py

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Contributed on Sep 17 2020

Determined Dormouse

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sort dict by value

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>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Source: stackoverflow.com

Tags: python py

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Contributed on Nov 25 2020

Poor Panther

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python sort array of dictionary by value

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my_list = sorted(my_list, key=lambda k: k['name'])

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Source: stackoverflow.com

Tags: dictionary d

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Contributed on Apr 19 2021

Grotesque Goshawk

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python order list of dictionaries by value

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newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])

Popularity 7/10 Helpfulness 4/10 Language python

Source: stackoverflow.com

Tags: list python

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Contributed on Nov 14 2022

FishBrawler

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How to sort a Python dict by value

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# How to sort a Python dict by value
# (== get a representation sorted by value)

>>> xs = {'a': 4, 'b': 3, 'c': 2, 'd': 1}

>>> sorted(xs.items(), key=lambda x: x[1])
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

# Or:

>>> import operator
>>> sorted(xs.items(), key=operator.itemgetter(1))
[('d', 1), ('c', 2), ('b', 3), ('a', 4)]

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Tags: python py

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Contributed on Jul 03 2022

OHIOLee

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sort dict by value

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d = {'one':1,'three':3,'five':5,'two':2,'four':4}
a = sorted(d.items(), key=lambda x: x[1])    
print(a)

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Source: stackoverflow.com

Tags: python py

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Contributed on Sep 10 2022

Breakable Buffalo

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python sort dict by value

Comment

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A, key=A.get)}

output:
{4: -20, 1: 2, -1: 4}

Popularity 10/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: python py

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Contributed on Oct 15 2020

IJustWannaHelp

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order list of dict by dict value

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