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xmpp server register

Andrew Charles Powell answered on March 8, 2023 Popularity 2/10 Helpfulness 1/10

answer xmpp server register

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import xmpp

conn = xmpp.Client(ipaddress)
conn.connect((ipaddress,5222), secure=0)
conn.auth(user,passwd,sasl=1) # Admin user
conn.sendInitPresence()

xmpp.features.register(conn, "<vhost>", {'username': 'satish', 'password': 'password'})

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Source: stackoverflow.com

Tags: server whatever xmpp

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Contributed on Mar 08 2023

Andrew Charles Powell

0 Answers Avg Quality 2/10

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import xmlrpclib
server_url = 'http://127.0.0.1:4560'
server = xmlrpclib.ServerProxy(server_url)
EJABBERD_XMLRPC_LOGIN = {'user': 'user1', 'server': 'localhost', 'password': 'mypass11', 'admin': True}
def ejabberdctl1(command, data):
    fn = getattr(server, command)
    return fn(data)
def ejabberdctl2(command, data):
    fn = getattr(server, command)
    return fn(EJABBERD_XMLRPC_LOGIN, data)
print ""
result = ejabberdctl1('srg_get_info', {'group':'group1', 'host':'localhost'})
print result

Popularity 2/10 Helpfulness 1/10 Language whatever

Source: github.com

Tags: server xmpp whatever

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Contributed on Mar 08 2023

Andrew Charles Powell

0 Answers Avg Quality 2/10

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