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tide framwork simple server

Himanshu Jangid answered on April 14, 2023 Popularity 1/10 Helpfulness 1/10

answer tide framwork simple server

tide framwork simple server

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use tide::Request;
use tide::prelude::*;

#[derive(Debug, Deserialize)]
struct Animal {
    name: String,
    legs: u8,
}

#[async_std::main]
async fn main() -> tide::Result<()> {
    let mut app = tide::new();
    app.at("/orders/shoes").post(order_shoes);
    app.listen("127.0.0.1:8080").await?;
    Ok(())
}

async fn order_shoes(mut req: Request<()>) -> tide::Result {
    let Animal { name, legs } = req.body_json().await?;
    Ok(format!("Hello, {}! I've put in an order for {} shoes", name, legs).into())
}

Popularity 1/10 Helpfulness 1/10 Language rust

Source: docs.rs

Tags: rust server

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Contributed on Apr 14 2023

Himanshu Jangid

0 Answers Avg Quality 2/10

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tide framwork simple server

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