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Number 10

Marlon Oquina answered on March 3, 2022 Popularity 3/10 Helpfulness 1/10

answer Number 10

Number 10

Comment

#include <stdio.h>
int main() 
{ 
    int a = 30;  
    int b = 10;  
    int c = 15; 
    int d = 5; 
    int e;  
    e = (a + b) * c / d;
  
    // ( 30 * 15 ) / 5  
    printf("Value of (a + b) * c / d is : %d\n", e );  
    e = ((a + b) * c) / d; 
  
    // (30 * 15 ) / 5  
    printf("Value of ((a + b) * c) / d is : %d\n" , e ); 
    e = (a + b) * (c / d); 
  
   // (30) * (15/5)  
   printf("Value of (a + b) * (c / d) is : %d\n", e );  
   e = a + (b * c) / d;  
  
   // 30 + (150/5)  
   printf("Value of a + (b * c) / d is : %d\n" , e );  
   return 0;  
}

Popularity 3/10 Helpfulness 1/10 Language c

Source: www.codegrepper.com

Tags: c

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