Breaking News: Grepper is joining You.com. Read the official announcement!

inorder traversal of tree

Add Answer

Unusual Unicorn answered on March 24, 2021 Popularity 10/10 Helpfulness 2/10

answer inorder traversal of tree

related preorder traversal

related Inorder traversal Algorithm for binary tree

related inorder traversal search

inorder traversal of tree

Comment

//*******this is a C program for implementation and searching in A BT*******
#include<stdlib.h>
#include <stdio.h>

struct BinaryTree{
    int data;
    struct BinaryTree*right;
    struct BinaryTree*left;
};

struct BinaryTree*createnode(int val){
    struct BinaryTree*root=(struct BinaryTree*)malloc(sizeof(struct BinaryTree));
    root->data=val;
    root->left=NULL;
    root->right=NULL;
    
}

void inorder(struct BinaryTree*root){
    if(root==NULL){
    return;
    }
    else {inorder(root->left);
    printf("%d->",root->data);
    inorder(root->right);
}

}
 
void preorder(struct BinaryTree*root){
    if(root==NULL){
        return;
    }
    else {
        printf("%d->",root->data);
        preorder(root->left);
        preorder(root->right);
    }
}

void postorder(struct BinaryTree*root){
    if(root==NULL){
        return;
    }
    else{
        postorder(root->left);
        postorder(root->right);
        printf("%d->",root->data);
    }
}
int main()
{
    printf("Lets grow the tree\n");
    struct BinaryTree*root=createnode(1);
    root->left=createnode(2);
    root->right=createnode(3);
    root->left->left=createnode(4);
    root->left->right=createnode(5);
    
    printf("tree has grown up\n");
    
    printf("Inorder traversal ");
    inorder(root);printf("NULL");

    printf("\npreorder traversal ");
    preorder(root);printf("NULL");
    
    printf("\nPostorder  traversal");
    postorder(root);printf("NULL");
    
    return 0 ;
}

Popularity 10/10 Helpfulness 2/10 Language c

Source: Grepper

Tags: c inorder traversal tree

Link to this answer
Share Copy Link

Contributed on Aug 17 2022

Unusual Unicorn

0 Answers Avg Quality 2/10

Closely Related Answers

preorder traversal

Comments(1)

<> Preorder		Root -> Left -> Right 
<> Inorder		Left -> Root -> Right
<> Postorder	Left -> Right -> Root

Popularity 10/10 Helpfulness 4/10 Language javascript

Source: Grepper

Tags: depth-first-search depth-first-searc

Link to this answer
Share Copy Link

Contributed on Jan 09 2023

correctYourPosture

0 Answers Avg Quality 2/10

Inorder traversal Algorithm for binary tree

Comment

Until all nodes are traversed −
Step 1 − Recursively traverse left subtree.
Step 2 − Visit root node.
Step 3 − Recursively traverse right subtree.

Popularity 10/10 Helpfulness 2/10 Language whatever

Source: www.tutorialspoint.com

Tags: algorithm algo

Link to this answer
Share Copy Link

Contributed on Sep 22 2022

Taiwo Adedotun

0 Answers Avg Quality 2/10

inorder traversal search

Comment

class Node:
    def __init__(self, key):
        self.left = None
        self.right = None
        self.val = key

def printInorder(root):
    if root:
        printInorder(root.left)
        print(root.val),
        printInorder(root.right)

if __name__ == "__main__":
    root = Node(1)
    root.left = Node(2)
    root.right = Node(3)
    root.left.left = Node(4)
	root.left.right = Node(5)

print("\n Inorder traversal of binary tree is")
printInorder(root)
print(root)

Popularity 9/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: inorder

Link to this answer
Share Copy Link

Contributed on Oct 07 2022

Adam, the developer

0 Answers Avg Quality 2/10

Postorder Traversal

Comment

# Assuming valid Binary Tree Node
def post_order(node: BinaryTreeNode):
    if node.left:
        post_order(node.left)
    if node.right:
        post_order(node.right)
    print(node.val)

Popularity 9/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: postorder post

Link to this answer
Share Copy Link

Contributed on Jul 24 2023

Hassan

0 Answers Avg Quality 2/10

Postorder traversal

Comment

class Solution {
    List<Integer> list = new ArrayList<>();
    public List<Integer> postorderTraversal(TreeNode root) {
        dfs(root);
        return list;
        
    }
     public void dfs(TreeNode root)
    {
        if(root!=null)
        {
            
            dfs(root.left);
            
            dfs(root.right);
            list.add(root.val);
        }
    }
}

Popularity 9/10 Helpfulness 1/10 Language whatever

Source: Grepper

Tags: postorder post

Link to this answer
Share Copy Link

Contributed on Jun 22 2023

Zealous Zebra

0 Answers Avg Quality 2/10

Tree: Postorder Traversal

Comment

def postOrder(root):
    if root:
        postOrder(root.left)
        postOrder(root.right)
        print(root, end = " ")

Popularity 10/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: postorder post

Link to this answer
Share Copy Link

Contributed on Jun 18 2022

Grieving Gazelle

0 Answers Avg Quality 2/10

preorder traversal c++

Comment

a
s
d

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: c++ preorder traversal

Link to this answer
Share Copy Link

Contributed on Mar 24 2021

Jolly Jackal

0 Answers Avg Quality 2/10

preorder traversal of binary tree c++

Comment

#include <bits/stdc++.h>

using namespace std;

struct node {
  int data;
  struct node * left, * right;
};

vector < int > preOrderTrav(node * curr) {
  vector < int > preOrder;
  if (curr == NULL)
    return preOrder;

  stack < node * > s;
  s.push(curr);

  while (!s.empty()) {
    node * topNode = s.top();
    preOrder.push_back(topNode -> data);
    s.pop();
    if (topNode -> right != NULL)
      s.push(topNode -> right);
    if (topNode -> left != NULL)
      s.push(topNode -> left);
  }
  return preOrder;

}

struct node * newNode(int data) {
  struct node * node = (struct node * ) malloc(sizeof(struct node));
  node -> data = data;
  node -> left = NULL;
  node -> right = NULL;

  return (node);
}

int main() {

  struct node * root = newNode(1);
  root -> left = newNode(2);
  root -> right = newNode(3);
  root -> left -> left = newNode(4);
  root -> left -> right = newNode(5);
  root -> left -> right -> left = newNode(8);
  root -> right -> left = newNode(6);
  root -> right -> right = newNode(7);
  root -> right -> right -> left = newNode(9);
  root -> right -> right -> right = newNode(10);

  vector < int > preOrder;
  preOrder = preOrderTrav(root);

  cout << "The preOrder Traversal is : ";
  for (int i = 0; i < preOrder.size(); i++) {
    cout << preOrder[i] << " ";
  }
  return 0;
}

Popularity 8/10 Helpfulness 1/10 Language cpp

Source: takeuforward.org

Tags: binary-tree bina

Link to this answer
Share Copy Link

Contributed on Dec 10 2023

Hitesh Prajapati

0 Answers Avg Quality 2/10

Preorder, inorder & postorder traversal code

Comments(1)

class Node:
    def __init__(self, k):
        self.left = None
        self.right = None
        self.key = k


def inorder(root):
    if root != None:
        inorder(root.left)
        print(root.key)
        inorder(root.right)


# Driver Code

root = Node(10)
root.left = Node(20)
root.right = Node(30)
root.right.left = Node(40)
root.right.right = Node(50)

inorder(root)

# time complexity (using recurrence tree method)  - O(n)
where, 
n == total nodes 
# space complexity - O(height of tree)
Note: height can be both n (if each node has exactly 1 child) and 
log(n) (if every node has exactly 2 children).

# IMP NOTE : FOR PREORDER AND POSTORDER JUST ORDER OF STATEMENTS CHANGE

for ex:
below is preorder & postorder traversal with same time & space complexity as inorder

def preorder(root):
    if root == None:
        return
    print(root.key)
    preorder(root.left)
    preorder(root.right)

def postorder(root):
    if root == None:
        return
    preorder(root.left)
    preorder(root.right)
    print(root.key)

Popularity 10/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: inorder

Link to this answer
Share Copy Link

Contributed on Aug 04 2022

ap_Cooperative_dev

0 Answers Avg Quality 2/10

inorder traversal of tree

Contents

More Related Answers

inorder traversal of tree

Closely Related Answers

preorder traversal

Inorder traversal Algorithm for binary tree

inorder traversal search

Postorder Traversal

Postorder traversal

Tree: Postorder Traversal

preorder traversal c++

preorder traversal of binary tree c++

Preorder, inorder & postorder traversal code

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.