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tick marks in latex

Stormy Salamander answered on August 4, 2022 Popularity 9/10 Helpfulness 2/10

answer tick marks in latex

tick marks in latex

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\documentclass{amsart}
\usepackage{amsmath}
\usepackage{tikz}
\usepackage{xparse}
\usetikzlibrary{calc,angles,positioning,intersections,quotes,decorations.markings}

\tikzset{
  triple/.style args={[#1] in [#2] in [#3]}{
  #1,preaction={preaction={draw,#3},draw,#2}
  }
}

\NewDocumentCommand\bisector{O{}mmmO{10pt}}{
  \path[#1] let
    \p1 = ($(#3)!1cm!(#2)$),
    \p2 = ($(#3)!1cm!(#4)$),
    \p3 = ($(\p1) + (\p2) - (#3)$)
    in    
    ($(#3)!#5!($(#3)!1cm!(\p3)$)$) -- ($($(#3)!1cm!(\p3)$)!#5!(#3)$) ;
}

\begin{document}

\noindent \hspace*{\fill}
\begin{tikzpicture}

%Parallelogram ABCD and its diagonals are drawn.
\coordinate (A) at (0,0);
\coordinate (B) at (75:3);
\coordinate (C) at ($(B) +(5,0)$);
\coordinate (D) at ($(C) +(-105:3)$);

\draw (A) -- (B) -- (C) -- (D) -- cycle;

\draw[name path=path_AC] (A) -- (C);
\draw[name path=path_BD] (B) -- (D);

%The four vertices are labeled.
\node at ($(A)! -2.5mm! (C)$){$A$};
\node at ($(B)! -2.5mm! (D)$){$B$};
\node at ($(C)! -2.5mm! (A)$){$C$};
\node at ($(D)! -2.5mm! (B)$){$D$};

%The intersection of the diagonals of the parallelogram is P.  To place
%the label for P, the line segments are extended 4mm by an invisible
%path command "above" P. The endpoints of these extensions are called
%"label_P_left" and "label_P_right" and the midpoint of the line segment
%between them is called "label_P".  A node command typesets "P" at the
%point 2.5mm from P on the invisible line segment between P and label_P.
\coordinate[name intersections={of=path_AC and path_BD, by={P}}];

\coordinate (label_P_left) at ($(P)!-4mm!(D)$);
\coordinate (label_P_right) at ($(P)!-4mm!(A)$);
\coordinate (label_P) at ($(label_P_left)!0.5!(label_P_right)$);
\node[blue] at ($(P)!2.5mm!(label_P)$){$P$};


%Opposite sides of the parallelogram are marked to indicate that they are
%congruent.

\coordinate (mark_for_AD) at ($(A)!0.5!(D)$);
\draw ($(mark_for_AD) + (0pt,-4pt)$) -- ($(mark_for_AD) + (0pt,4pt)$);
\coordinate (mark_for_BC) at ($(B)!0.5!(C)$);
\draw ($(mark_for_BC) + (0pt,-4pt)$) -- ($(mark_for_BC) + (0pt,4pt)$);

\coordinate (mark_for_AB) at ($(A)!0.5!(B)$);
\coordinate (mark_for_AB_up) at ($(mark_for_AB)! 1pt! (B)$);
\coordinate (mark_for_AB_down) at ($(mark_for_AB)! 1pt! (A)$);
\draw ($(mark_for_AB_up)!4pt!-90:(A)$) -- ($(mark_for_AB_up)!4pt!-90:(B)$);
\draw ($(mark_for_AB_down)!4pt!-90:(A)$) -- ($(mark_for_AB_down)!4pt!-90:(B)$);

\coordinate (mark_for_CD) at ($(C)!0.5!(D)$);
\coordinate (mark_for_CD_up) at ($(mark_for_CD)! 1pt! (C)$);
\coordinate (mark_for_CD_down) at ($(mark_for_CD)! 1pt! (D)$);
\draw ($(mark_for_CD_up)!4pt!-90:(D)$) -- ($(mark_for_CD_up)!4pt!-90:(C)$);
\draw ($(mark_for_CD_down)!4pt!-90:(D)$) -- ($(mark_for_CD_down)!4pt!-90:(C)$);

% Marks for the angles
\bisector[draw]{A}{B}{P}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = A--B--P};
\bisector[draw]{C}{D}{P}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = C--D--P};
\bisector[draw,double]{P}{B}{C}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = P--B--C};
\bisector[draw,double]{P}{D}{A}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = P--D--A};

\bisector[draw,
  triple={[line width=0.4pt] in
    [line width=2pt,white] in
    [line width=2.8pt]}
  ]{B}{P}{A}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = B--P--A};
\bisector[draw,
  triple={[line width=0.4pt] in
    [line width=2pt,white] in
    [line width=2.8pt]}
  ]{C}{P}{D}
\draw[black] 
  pic [draw,angle eccentricity=1]
  {angle = D--P--C};
\end{tikzpicture}

\end{document}

Popularity 9/10 Helpfulness 2/10 Language whatever

Source: newbedev.com

Tags: latex whatever

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Contributed on Aug 04 2022

Stormy Salamander

0 Answers Avg Quality 2/10

tick marks in latex

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