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level order traversal of tree c

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whoibrar answered on May 1, 2022 Popularity 9/10 Helpfulness 1/10

answer level order traversal of tree c

related binary tree level order traversal

related level order traversal of binary tree c++

level order traversal of tree c

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// Recursive C program for level
// order traversal of Binary Tree
#include <stdio.h>
#include <stdlib.h>
 
/* A binary tree node has data,
   pointer to left child
   and a pointer to right child */
struct node {
    int data;
    struct node *left, *right;
};
 
/* Function prototypes */
void printCurrentLevel(struct node* root, int level);
int height(struct node* node);
struct node* newNode(int data);
 
/* Function to print level order traversal a tree*/
void printLevelOrder(struct node* root)
{
    int h = height(root);
    int i;
    for (i = 1; i <= h; i++)
        printCurrentLevel(root, i);
}
 
/* Print nodes at a current level */
void printCurrentLevel(struct node* root, int level)
{
    if (root == NULL)
        return;
    if (level == 1)
        printf("%d ", root->data);
    else if (level > 1) {
        printCurrentLevel(root->left, level - 1);
        printCurrentLevel(root->right, level - 1);
    }
}
 
/* Compute the "height" of a tree -- the number of
    nodes along the longest path from the root node
    down to the farthest leaf node.*/
int height(struct node* node)
{
    if (node == NULL)
        return 0;
    else {
        /* compute the height of each subtree */
        int lheight = height(node->left);
        int rheight = height(node->right);
 
        /* use the larger one */
        if (lheight > rheight)
            return (lheight + 1);
        else
            return (rheight + 1);
    }
}
 
/* Helper function that allocates a new node with the
   given data and NULL left and right pointers. */
struct node* newNode(int data)
{
    struct node* node
        = (struct node*)malloc(sizeof(struct node));
    node->data = data;
    node->left = NULL;
    node->right = NULL;
 
    return (node);
}
 
/* Driver program to test above functions*/
int main()
{
    struct node* root = newNode(1);
    root->left = newNode(2);
    root->right = newNode(3);
    root->left->left = newNode(4);
    root->left->right = newNode(5);
 
    printf("Level Order traversal of binary tree is \n");
    printLevelOrder(root);
 
    return 0;
}

Popularity 9/10 Helpfulness 1/10 Language c

Source: www.geeksforgeeks.org

Tags: c traversal tree

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Contributed on Sep 02 2022

whoibrar

0 Answers Avg Quality 2/10

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binary tree level order traversal

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/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<List<Integer>> levelOrder(TreeNode root) {
        List<List<Integer>> list = new ArrayList<>();
        Deque<TreeNode> queue = new ArrayDeque<>();
        if(root==null)
            return list;
        queue.offerLast(root);
        while(!queue.isEmpty())
        {
            ArrayList<Integer> l= new ArrayList<>();
            int size=queue.size();
            for(int i=0;i<size;i++)
            {
                TreeNode node=queue.pollFirst();
                if(node.left!=null)
                    queue.offerLast(node.left);
                if(node.right!=null)
                    queue.offerLast(node.right);
                l.add(node.val);

            }
            list.add(l);

        }

        return list;
        
        
    }
}

Popularity 9/10 Helpfulness 1/10 Language java

Source: Grepper

Tags: binary-tree bina

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Contributed on Jun 22 2023

Zealous Zebra

0 Answers Avg Quality 2/10

level order traversal of binary tree c++

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/*
node class contains:
node* left;
node* right;
int value;
*/
void levelOrder(node* root){
  node* ptr=nullptr;
  queue<node*> q;
  q.push(root);
  while(!q.empty()){
    ptr=q.front();
    cout<<ptr->value<<endl;
    if(ptr->left!=nullptr){
q.push(ptr->left);
  }
    if(ptr->right!=nullptr){
    q.push(ptr->right);
    }
    q.pop();
  }
}

Popularity 10/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: binary-tree bina

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Contributed on May 01 2022

Shiny Spider

0 Answers Avg Quality 2/10

level order traversal of tree c

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