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python code for quadratic equation

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Pelumi Olawole answered on September 30, 2020 Popularity 8/10 Helpfulness 6/10

answer python code for quadratic equation

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python code for quadratic equation

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from math import sqrt

def quadratic(a, b, c):
    x1 = -b / (2*a)
    x2 = sqrt(b**2 - 4*a*c) / (2*a)
    return (x1 + x2), (x1 - x2)

Popularity 8/10 Helpfulness 6/10 Language python

Source: treyhunner.com

Tags: equation python quadratic

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Contributed on Aug 03 2022

Pelumi Olawole

0 Answers Avg Quality 2/10

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quadratic formula python

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from cmath import sqrt as c_sqrt
from math import sqrt as m_sqrt
import tkinter as tk

# creates and runs an instance of the window
window = tk.Tk()

#makes the size of the widow
window.geometry("600x400")

#sets a title for the screen
window.title("intercode")

# creating a new label and adding a text to the window
new_label=tk.Label(window,text='enter a,b,c quadratic formula\n')
new_label.pack()

#creates a entrybox to add words to window
entry_label1=tk.Entry(window)
entry_label1.pack()

entry_label2=tk.Entry(window)
entry_label2.pack()

entry_label3=tk.Entry(window)
entry_label3.pack()
# defines results as string var
results= tk.StringVar(window)



#creating a results label
result_lable=tk.Label(window,textvariable=results)
result_lable.pack()



def callbackfunct():
    a =entry_label1.get()
    b =entry_label2.get()
    c =entry_label3.get()
    try:
        a= float(a)
        b= float(b)
        c= float(c)

    except ValueError:
        results.set("\nEnter number.")


    if (b**2-4*a*c) < 0:
        minus = (-b-c_sqrt(b**2-4*a*c))/(2*a)
        plus = (-b+c_sqrt(b**2-4*a*c))/(2*a)
    else:
        minus = (-b-m_sqrt(b**2-4*a*c))/(2*a)
        plus = (-b+m_sqrt(b**2-4*a*c))/(2*a)
        
    # deletes the text in the text box
    entry_label1.delete(0,tk.END)
    entry_label2.delete(0,tk.END)
    entry_label3.delete(0,tk.END)

    var = (f"'B+'   {plus} , 'B-'   {minus}")
    results.set(var)
# creating a button with a command
buttonez = tk.Button(text="Submit", command=callbackfunct)
buttonez.pack()

window.mainloop()

Popularity 9/10 Helpfulness 7/10 Language python

Source: Grepper

Tags: calculator c

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Contributed on Nov 03 2022

An7wan

0 Answers Avg Quality 2/10

Python Program to Solve Quadratic Equation

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roots = ( -b + sqrt(b ^ 2 - 4 * a *c) ) / (2 * a)   , ( -b - sqrt(b ^ 2 - 4 * a *c) ) / (2 * a)

Popularity 9/10 Helpfulness 5/10 Language python

Source: btechgeeks.com

Tags: equation equatio

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Contributed on Jun 25 2021

Quaint Quoll

0 Answers Avg Quality 2/10

quadratic equation python

Comment

print ("ax2 + bx + c = 0")
a = float(input("a: "))
b = float(input("b: "))
c = float(input("c: "))
delta = (b**2) - (4*a*c)
answers = []
numerator = [-b + delta**0.5, -b - delta**0.5]

denominator= 2 * a

for i in range(2):
    ans = numerator[i] / denominator
    answers.append(ans)
print (answers)

Popularity 9/10 Helpfulness 4/10 Language python

Source: Grepper

Tags: equation equatio

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Contributed on Jan 30 2022

BGOPC

0 Answers Avg Quality 2/10

python basic programs quadratic equation

Comment

(-b ± (b ** 2 - 4 * a * c) ** 0.5) / (2 * a)

Popularity 7/10 Helpfulness 3/10 Language python

Source: www.programiz.com

Tags: basic equation python pytho

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Contributed on Jul 26 2022

Jinn world

0 Answers Avg Quality 2/10

python basic programs quadratic equation

Comment

ax2 + bx + c = 0, where
a, b and c are real numbers and
a ≠ 0

Popularity 7/10 Helpfulness 2/10 Language python

Source: www.programiz.com

Tags: basic equation equa

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Contributed on Jul 26 2022

Jinn world

0 Answers Avg Quality 2/10

quadratic equations in python

Comment

-1

def square(n):
  num=n
  newnum=n*n
  return newnum

Popularity 9/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: equations equa

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Contributed on Sep 30 2020

Anxious Anteater

0 Answers Avg Quality 2/10

python code for quadratic equation

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