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regex match brackets

Defiant Dragonfly answered on August 4, 2021 Popularity 10/10 Helpfulness 7/10

answer regex match brackets

related Match brackets

regex match brackets

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\[.*?\]

Popularity 10/10 Helpfulness 7/10 Language whatever

Source: Grepper

Tags: brackets match regex whatever

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Contributed on Aug 04 2021

Defiant Dragonfly

0 Answers Avg Quality 2/10

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Match brackets

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/*
  Have the function SearchingChallenge(str) take the str parameter being 
  passed and return 1 #ofBrackets if the brackets are correctly matched and each 
  one is accounted for. Otherwise return 0. 
  For example: if str is "(hello [world])(!)", 
  then the output should be 1 3 because all the brackets are matched and 
  there are 3 pairs of brackets, but if str is "((hello [world])" the the output 
  should be 0 because the brackets do not correctly match up. 
  Only "(", ")", "[", and "]" will be used as brackets. If str contains no brackets 
  return 1.
    Examples
    	Input: "(coder)[byte)]"
    		Output: 0
        Input: "(c([od]er)) b(yt[e])"
        	Output: 1 5

*/

const SearchingChallenge = str => { 
  let result;

  // code goes here
  // if str Contains no brackets
  if(!/[()[\]]/g.test(str)) result = 1
  else{
    // Initialized object to store pairing backets
    const pairingBrackets = {}

    // Replace or remove non-brackets to brackets if true
    const bracketsLeft = str.replace(/[^()[\]]/g, "").split('')

    // Create a counter for matching brackets
    bracketsLeft.forEach((elem) => 
      pairingBrackets[elem] === undefined ? pairingBrackets[elem] =1
      : pairingBrackets[elem] += 1
    )

    // if counters match, brackets condition is met and returns true
    const isBracketSame = pairingBrackets['('] === pairingBrackets[')']
    const isSquareBracketSame = pairingBrackets['['] === pairingBrackets[']']
    const isMatched = isBracketSame + isSquareBracketSame

    // Correctly matched if isMatched returns 2
    // Sum either counters ["(" or ")"] and ["[" or "]"]
    const totalNumberOfPairs = pairingBrackets[')'] + pairingBrackets['[']
    if(isMatched % 2 === 0) result = `${1} ${totalNumberOfPairs}`
    else result = 0
  }
  
  return result
}
   
// keep this function call here 
console.log(SearchingChallenge("(c([od]er)) b(yt[e])"));

Popularity 4/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: brackets javascript match

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Contributed on Nov 02 2022

kouqhar

0 Answers Avg Quality 2/10

regex match brackets

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regex match brackets

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Match brackets

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