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Nth catalan number

Helper answered on December 27, 2021 Popularity 8/10 Helpfulness 2/10

answer Nth catalan number

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Nth catalan number

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Recursion :

def findCatalan(n):
    def recur(n):
        if n == 0 or n == 1:
            return 1
        res = 0
        for i in range(n):
            res += recur(i) * recur(n-i-1)
        return res
    return recur(n)

Top down :

def findCatalan(n): 
    def top_down(n,dp):
        if dp[n] != -1:
            return dp[n]
        res = 0
        for i in range(n):
            res += top_down(i,dp) * top_down(n-i-1,dp)
        dp[n] = res
        return dp[n]
    
    dp = [-1] * (n+1)
    dp[0] = 1
    dp[1] = 1
    return top_down(n,dp)

Bottom Up:

def findCatalan(n): 
    def bottom_up(n,dp):
        for i in range(2,n+1):
            for j in range(i):
                dp[i]  += dp[j] * dp[i-j-1]
    
    dp = [0] * (n+1)
    dp[0] = 1
    dp[1] = 1
    bottom_up(n,dp) # Calling function
    return dp[n]

Popularity 8/10 Helpfulness 2/10 Language python

Source: practice.geeksforgeeks.org

Tags: catalan python

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Contributed on Dec 27 2021

Helper

0 Answers Avg Quality 2/10

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nth catalan number

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class Solution575
{
    static BigInteger[] catalan = new BigInteger[101];

    static{
        catalan[0] = new BigInteger("1");
        catalan[1] = new BigInteger("1");
    }

    //Function to find the nth catalan number.
    public static BigInteger findCatalan(int n)
    {
        //Your code here
        if(catalan[n]!=null){
            return catalan[n];
        }

        BigInteger total = new BigInteger("0");
        for(int i=0;i<n;i++){
            total = total.add(findCatalan(i).multiply(findCatalan(n-i-1)));
        }
        catalan[n] = total;
        return total;
    }
}

Popularity 7/10 Helpfulness 1/10 Language whatever

Source: Grepper

Tags: catalan whatever

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Contributed on Oct 19 2022

Sumit Rawal

0 Answers Avg Quality 2/10

Nth catalan number

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