No enclosing instance of type Foo is accessible. Must qualify the allocation with an enclosing instance of type Foo (e.g. x.new A() where x is an instance of Foo

Pleasant Pigeon answered on December 30, 2021 Popularity 9/10 Helpfulness 1/10

answer No enclosing instance of type Foo is accessible. Must qualify the allocation with an enclosing instance of type Foo (e.g. x.new A() where x is an instance of Foo

No enclosing instance of type Foo is accessible. Must qualify the allocation with an enclosing instance of type Foo (e.g. x.new A() where x is an instance of Foo

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static class SimpleCircle

Popularity 9/10 Helpfulness 1/10 Language java

Source: stackoverflow.com

Tags: allocation instance java where

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Contributed on Jan 12 2022

Pleasant Pigeon

0 Answers Avg Quality 2/10

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No enclosing instance of type Main is accessible. Must qualify the allocation with an enclosing instance of type Main (e.g. x.new A() where x is an instance of Main).

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public class TestSimpleCircle {

    class SimpleCircle {
        double radius;

        SimpleCircle(){
            radius = 1;
        }

        SimpleCircle(double newRadius){
            radius = newRadius;
        }

        double getArea() {
            return radius * radius * Math.PI;
        }

        double getPerimeter() {
            return 2 * radius * Math.PI;
        }

        void setRadius(double newRadius) {
            radius = newRadius;
        }
    }

    public static void main(String [] args) {
        SimpleCircle circle = new SimpleCircle();
        System.out.println("the area of the circle of radius "+circle.radius+" is "+circle.getArea());

        SimpleCircle circle2 = new SimpleCircle(25);
        System.out.println("the area of the circle of radius "+circle2.radius+" is "+circle2.getArea());

        SimpleCircle circle3 = new SimpleCircle(125);
        System.out.println("the area of the circle of radius "+circle3.radius+" is "+circle3.getArea());

        circle.radius = 100;
        System.out.println("The area of the circle of radius "+circle.radius+" is "+circle.getArea());
    }
}

Popularity 9/10 Helpfulness 1/10 Language java

Source: stackoverflow.com

Tags: allocation a

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Contributed on Dec 30 2021

Selfish Seahorse

0 Answers Avg Quality 2/10

No enclosing instance of type Foo is accessible. Must qualify the allocation with an enclosing instance of type Foo (e.g. x.new A() where x is an instance of Foo

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No enclosing instance of type Foo is accessible. Must qualify the allocation with an enclosing instance of type Foo (e.g. x.new A() where x is an instance of Foo

Closely Related Answers

No enclosing instance of type Main is accessible. Must qualify the allocation with an enclosing instance of type Main (e.g. x.new A() where x is an instance of Main).

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