Contents

answer val = int(input()) for x in range (0, val): print('*' * val)

More Related Answers

python print range

Write a Python function to check whether a number is in a given range.

for num in range(10, 14): for i in range(2, num): if num%i == 1: print(num) break

is out of range for type integer

0 for i in range(n)

is range inclusive python

a=input("enter the number whose table you want to see") for i in range(0,11): print( %s,'x',i,'=' , %s *i,(a))

for x in range(1,100, 10): print(x)

for x in range(1, 10, 3): print(x)

for i in range(1, 11): print(i, end="")

for i in range(1, 11): print(i, end="")

for i in range(6, 11): print(i, end="")

for x in range(1,100, 10): print(x)

for y in range(10): for x in range(y): print("*",end='') print()

python interpolation string show number with 0

random integers function to print integers with in a range

random integers function to print integers with in a range

random integers function to print integers with in a range

random integers function to print integers with in a range

random integers function to print integers with in a range

random integers function to print integers with in a range

name for a value in range [0,1]

I need to write an int function in which there are only cout statements and if I return 0/1 it prints them too.