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minimum swaps

Bored Beaver answered on August 12, 2022 Popularity 5/10 Helpfulness 1/10

answer minimum swaps

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minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: minimum python

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Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

Closely Related Answers

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 8/10 Helpfulness 3/10 Language python

Source: www.thepoorcoder.com

Tags: minimum python minim

Link to this answer
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Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 2/10 Language python

Source: www.thepoorcoder.com

Tags: minimum python

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 6/10 Helpfulness 2/10 Language python

Source: www.thepoorcoder.com

Tags: minimum python

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: python minimum

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: python minimum

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: python minimum

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: minimum python

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

Comment

python
def minimumSwaps(arr): 
    a = dict(enumerate(arr,1))
    b = {v:k for k,v in a.items()}
    count = 0
    for i in a:
        x = a[i]
        if x!=i:
            y = b[i]
            a[y] = x
            b[x] = y
            count+=1
    return count
        
n = int(input())
arr = list(map(int,input().split()))
print(minimumSwaps(arr))

Popularity 5/10 Helpfulness 1/10 Language python

Source: www.thepoorcoder.com

Tags: python minimum

Link to this answer
Share Copy Link

Contributed on Aug 12 2022

Bored Beaver

0 Answers Avg Quality 2/10

minimum swaps

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