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MONTH(L.joindate),

Demetrio Dela Rosa Jr answered on September 13, 2022 Popularity 1/10 Helpfulness 1/10

answer MONTH(L.joindate),

MONTH(L.joindate),

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select date_format(joindate, '%Y-%m-01') joinmonth,
    count(*) - lag(count(*), 1, 0) over(order by date_format(joindate, '%Y-%m-01')) m2m
from userlog
group by joinmonth

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Contributed on Sep 13 2022

Demetrio Dela Rosa Jr

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