Breaking News: Grepper is joining You.com. Read the official announcement!

create list recursively python

Prickly Pigeon answered on December 21, 2022 Popularity 6/10 Helpfulness 2/10

answer create list recursively python

related recursive list python

create list recursively python

Comment

def rec(S):
    if len(S) == 1:
        return S
    return S[-1] + rec(S[:-1])

Popularity 6/10 Helpfulness 2/10 Language python

Source: www.codingninjas.com

Tags: list python

Link to this answer
Share Copy Link

Contributed on Dec 21 2022

Prickly Pigeon

0 Answers Avg Quality 2/10

Closely Related Answers

recursive list python

Comment

class RecursiveList:
    """A recursive implementation of a List

    Representation Invariants:
        - (self._first is None) == (self._rest is None)
    """
    _first  # The first item in this list, or None if this list is empty.
    _rest:  # A list containing the items in this list that come after the first one, or None if this list is empty.

    def __init__(self, first, rest) -> None:
        """Initialize a new recursive list."""
        self._first = first
        self._rest = rest

    def is_empty(self) -> bool:
        """Return whether this list is empty.
        """
        return self._first is None

    def sum(self) -> int:
        """Return the sum of the elements in this list.
        """
        if self._first is None:  # Base case: this list is empty
            return 0
        else:
            return self._first + self._rest.sum()
	
    def to_list(self) -> list:
        """Return a Python list containing the items stored in this list.
        """
        if self.is_empty():
            return []
        elif self._rest is None:
            return self._first
        else:
            return [self._first] + self._rest.to_list()

    def __contains__(self, item) -> bool:
        """Return whether the given item is in this list.
        """
        if self.is_empty():
            return False
        elif self._rest is None:
        	return self._first == item
        else:
        	return item in self._rest or item == self._first

    def index(self, item) -> int:
        """Return the index of the first occurrence of the given item in this list.
        """
        if self.is_empty():
            raise ValueError
        elif self._first == item:
            return 0
        else:
            return 1 + self._rest.index(item)

    def insert(self, i: int, item) -> None:
        """Insert the given item in to this list at index i
        """
        if self.is_empty() and i > 0:
            raise IndexError
        elif i == 0:
            self._rest = RecursiveList(self._first, self._rest)
            self._first = item
        else:
            self._rest.insert(i - 1, item)

Popularity 6/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: python list

Link to this answer
Share Copy Link

Contributed on Feb 02 2023

The Amateur

0 Answers Avg Quality 2/10

create list recursively python

Contents

More Related Answers

create list recursively python

Closely Related Answers

recursive list python

Grepper

Documentation

Social

Legal

Contact

Oops, You will need to install Grepper and log-in to perform this action.