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permission dynamically in django

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Debugger Supreme answered on June 26, 2021 Popularity 9/10 Helpfulness 1/10

answer permission dynamically in django

related creating custom permissions in django

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permission dynamically in django

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from django.contrib.auth.models import User, Group, Permission
from django.contrib.contenttypes.models import ContentType

content_type = ContentType.objects.get(app_label='app_name', model='model_name')
permission = Permission.objects.create(codename='can_create_hr',
                                       name='Can create HR',
                                       content_type=content_type) # creating permissions
group = Group.objects.get(name='HR')
group.permissions.add(permission)

Popularity 9/10 Helpfulness 1/10 Language python

Source: stackoverflow.com

Tags: django python

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Contributed on Jan 24 2023

Debugger Supreme

0 Answers Avg Quality 2/10

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creating custom permissions in django

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class USCitizen(models.Model):
    # ...
    class Meta:
        permissions = (
            ("can_drive", "Can drive"),
            ("can_vote", "Can vote in elections"),
            ("can_drink", "Can drink alcohol"),
        )

Popularity 10/10 Helpfulness 2/10 Language python

Source: stackoverflow.com

Tags: django dj

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Contributed on Jun 26 2021

UG Legend

0 Answers Avg Quality 2/10

django programmatically create permissions

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from myapp.models import BlogPost
from django.contrib.auth.models import Permission
from django.contrib.contenttypes.models import ContentType

content_type = ContentType.objects.get_for_model(BlogPost)
permission = Permission.objects.create(
    codename='can_publish',
    name='Can Publish Posts',
    content_type=content_type,
)

Popularity 10/10 Helpfulness 2/10 Language python

Source: docs.djangoproject.com

Tags: django dj

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Contributed on Aug 30 2022

Sami Ferradji

0 Answers Avg Quality 2/10

permission dynamically in django

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permission dynamically in django

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creating custom permissions in django

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