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how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

victor onyedika answered on July 7, 2023 Popularity 1/10 Helpfulness 1/10

answer how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

Comment

ListView.builder(
  itemCount: 12,
  itemBuilder: (context, index) {
    // Calculate row and column indices
    int row = index ~/ 4;
    int col = index % 4;

    // Adjust position to fit desired layout
    return Column(
      children: [
        Row(
          children: [
            Container(), // Replace with your actual item widget
            Container(),
            Container(),
            Container(),
          ],
        ),
      ],
    );
  },
)

Popularity 1/10 Helpfulness 1/10 Language whatever

Source: chat.openai.com

Tags: listview whatever

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Contributed on Jul 07 2023

victor onyedika

0 Answers Avg Quality 2/10

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how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

Comment

ListView.builder(
  itemCount: 12,
  itemBuilder: (context, index) {
    // Calculate row and column indices
    int row = index ~/ 4;
    int col = index % 4;

    // Adjust position to fit desired layout
    return Column(
      children: [
        Row(
          children: [
            Container(), // Replace with your actual item widget
            Container(),
            Container(),
            Container(),
          ],
        ),
      ],
    );
  },
)

Popularity 1/10 Helpfulness 1/10 Language whatever

Source: chat.openai.com

Tags: listview whatever

Link to this answer
Share Copy Link

Contributed on Jul 07 2023

victor onyedika

0 Answers Avg Quality 2/10

how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

Comment

ListView.builder(
  itemCount: 12,
  itemBuilder: (context, index) {
    // Calculate row and column indices
    int row = index ~/ 4;
    int col = index % 4;

    // Adjust position to fit desired layout
    return Column(
      children: [
        Row(
          children: [
            Container(), // Replace with your actual item widget
            Container(),
            Container(),
            Container(),
          ],
        ),
      ],
    );
  },
)

Popularity 1/10 Helpfulness 1/10 Language whatever

Source: chat.openai.com

Tags: listview whatever

Link to this answer
Share Copy Link

Contributed on Jul 07 2023

victor onyedika

0 Answers Avg Quality 2/10

how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

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how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

Closely Related Answers

how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

how to use listview .builder efficiently that a container is into 4 horizotally and it is in 3 steps vertically with itemcount of 12

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