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Is there a better method to do this in Python if struct.unpack_from('>c', data)[0] in [b'\xA1'] and struct.unpack_from('>ccccccc', data)[6] in [b'\xA2']:

Alex answered on July 22, 2023 Popularity 1/10 Helpfulness 1/10

answer Is there a better method to do this in Python if struct.unpack_from('>c', data)[0] in [b'\xA1'] and struct.unpack_from('>ccccccc', data)[6] in [b'\xA2']:

Is there a better method to do this in Python if struct.unpack_from('>c', data)[0] in [b'\xA1'] and struct.unpack_from('>ccccccc', data)[6] in [b'\xA2']:

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import struct

data = b'\x00\x00\x00\xA1\x00\x00\x00\xA2'

# Unpack the data at once and check the conditions
if struct.unpack('>c c c c c c c', data) == (b'\x00', b'\x00', b'\x00', b'\xA1', b'\x00', b'\x00', b'\xA2'):
    print("Both conditions are satisfied.")
else:
    print("Conditions are not satisfied.")

Popularity 1/10 Helpfulness 1/10 Language python

Source: chat.openai.com

Tags: python this

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Contributed on Jul 22 2023

Alex

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Is there a better method to do this in Python if struct.unpack_from('>c', data)[0] in [b'\xA1'] and struct.unpack_from('>ccccccc', data)[6] in [b'\xA2']:

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Is there a better method to do this in Python if struct.unpack_from('>c', data)[0] in [b'\xA1'] and struct.unpack_from('>ccccccc', data)[6] in [b'\xA2']:

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