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quadratic equation solver

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YOU.com answered on December 31, 2021 Popularity 10/10 Helpfulness 1/10

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import cmath

def solve_quadratic(a, b, c):
    # Calculate the discriminant
    discriminant = (b**2) - (4*a*c)

    # Find two solutions
    solution1 = (-b - cmath.sqrt(discriminant)) / (2*a)
    solution2 = (-b + cmath.sqrt(discriminant)) / (2*a)

    return solution1, solution2

# Example usage
a = 1
b = -5
c = 6
solution1, solution2 = solve_quadratic(a, b, c)

print("Solutions: {0} and {1}".format(solution1, solution2))

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Contributed on Sep 12 2023

YOU.com

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quadratic equation

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Quadratic Equation are equations where the highest power of the variable (usually x) is 2, hence the word Quadratic Equations

The standard form of Quadratic Equations is as follows...

ax^2 + bx + c = 0 where a ≠ 0

This is because, even with an equation such as x^2 = 5, you can always* change it to the standard form.

x^2 = 5
x^2 - 5 = 0
x^2 - 5 + 0x = 0         ### 0 * x is 0 anyways so we can add that
x^2 + 0x - 5 = 0 
1x^2 + 0x - 5 = 0        ### 1 * x^2 is x^2 so we can add that (no change)

There! We got 1x^2 + 0x - 5 = 0!

You can cross check it with the standard form and see its the same!

Did you wonder why "a" can't be zero in the standard form? Well look here.

5x^2 + 10x + 20 = 0                 # PERFECTLY NORMAL QUADRATIC EQUATION 

0x^2 + 10x + 20 = 0                 # changing "a" to 0

10x + 20 = 0

At first glance, one may not notice the issue but let me pin point the definition of Quadratic Equation...

"Quadratic Equation are equations where the highest power of the variable is 2"

The definition states the highest power of x should be 2 but in 10x + 20 = 0 the highest power is 1 (where is no power, there is 1) so this equation became a linear equation! so to prevent that is why "a" or the coefficient of "x^2" can't equal to 0 in a Quadratic Equation

thank u! <3
NOW GO LEARN

-----------------
* = take with a pinch of salt

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Contributed on May 02 2024

Spiritual_Null

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quadratic equation

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(-b-sqrt(b**2-4*a*c))/(2*a)
(-b+sqrt(b**2-4*a*c))/(2*a)
If that doesn't work,
((0-b)-sqrt(b**2-4*a*c))/(2*a)
((0-b)+sqrt(b**2-4*a*c))/(2*a)

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Contributed on Dec 31 2021

Thankful Toucan

0 Answers Avg Quality 2/10

quadratic equation calculator

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import tkinter as tk
import cmath

root= tk.Tk()

root.title("Quadratic Solver")

canvas1 = tk.Canvas(root, width = 400, height = 300)
canvas1.pack()

entry1 = tk.Entry (root) 
canvas1.create_window(200, 60, window=entry1)

entry2 = tk.Entry (root) 
canvas1.create_window(200, 100, window=entry2)

entry3 = tk.Entry (root) 
canvas1.create_window(200, 140, window=entry3)


def solvequadratic ():
    a = int(entry1.get())
    b = int(entry2.get())
    c = int(entry3.get())

    label1 = tk.Label(root, text= ((-b-cmath.sqrt((b**2)-(4*a*c))/(2*a))))
    canvas1.create_window(200, 230, window=label1)
    label1 = tk.Label(root, text = ((-b+cmath.sqrt((b**2)-(4*a*c))/(2*a))))
    canvas1.create_window(200, 260, window=label1)
    
button1 = tk.Button(text='Solve Quadratic', command=solvequadratic)
canvas1.create_window(200, 180, window=button1)

root.mainloop()

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Contributed on Feb 21 2022

DifficultBozo

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quadratic equation

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Δ=b2−4ac 
(-b±√Δ)/2a

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Contributed on Jan 30 2022

BGOPC

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quadratic equation formula

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import math

def solve_quadratic_equation(a, b, c):
    discriminant = b**2 - 4*a*c
    
    if discriminant > 0:
        # Two distinct real roots
        root1 = (-b + math.sqrt(discriminant)) / (2*a)
        root2 = (-b - math.sqrt(discriminant)) / (2*a)
        return root1, root2
    elif discriminant == 0:
        # One real root
        root = -b / (2*a)
        return root
    else:
        # Complex roots
        real_part = -b / (2*a)
        imaginary_part = math.sqrt(abs(discriminant)) / (2*a)
        root1 = complex(real_part, imaginary_part)
        root2 = complex(real_part, -imaginary_part)
        return root1, root2

# Example usage with coefficients a, b, and c
a = 1
b = -3
c = 2

roots = solve_quadratic_equation(a, b, c)
print("Roots:", roots)

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Contributed on Sep 12 2023

YOU.com

0 Answers Avg Quality 2/10

quadratic equation solver

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