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def even_or_odd(number): return "Even" if number % 2 == 0 else "Odd"

Expensive Eel answered on July 29, 2022 Popularity 4/10 Helpfulness 1/10

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  • def even_or_odd(number): return "Even" if number % 2 == 0 else "Odd"

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    Source: github.com
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    Contributed on Oct 16 2023
    Expensive Eel
    0 Answers  Avg Quality 2/10

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