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gap_binario

Estevan Candido Pereira answered on March 22, 2022 Popularity 1/10 Helpfulness 1/10

answer gap_binario

gap_binario

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def solution(N):     
    binario = str(bin(N))[2:]
    grupo_binario = False
    binario_maior = 0
    bin_zero_counter = 0
    for char in binario:
        if char == '1':
            if binario_maior < bin_zero_counter:
                binario_maior = bin_zero_counter
            grupo_binario = True
            bin_zero_counter = 0
        elif grupo_binario:
            bin_zero_counter += 1
    return binario_maior
pass

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Contributed on Mar 22 2022

Estevan Candido Pereira

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