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insertion sort algorithm in descending order

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Philasande Hadebe answered on January 16, 2021 Popularity 1/10 Helpfulness 1/10

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insertion sort algorithm in descending order

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5 4 7 9

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Contributed on Apr 06 2022

Philasande Hadebe

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insertion sort

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#insertion sort
def insert(arr):
    for i in range(1,len(arr)):
        while arr[i-1] > arr[i] and i > 0:
            arr[i], arr[i-1] = arr[i-1], arr[i]
            i -= 1 
    return arr 
arr = [23, 55, 12, 99, 66, 33]
print(insert(arr))

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Tags: insertion-sort inse

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Contributed on Jul 24 2021

Kumaran KM

0 Answers Avg Quality 2/10

insertion sort

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*** Insertion sort ***
Enter some numbers : 1 2 3 4

[1, 2, 3, 4]
Data comparison =  3

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Source: datastruc.ce.kmitl.ac.th

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Contributed on Nov 24 2021

Clumsy Corncrake

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insertion sort

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#include <bits/stdc++.h>

using namespace std; 

void insertionSort(int arr[], int n)  
{  
    int i, temp, j;  
    for (i = 1; i < n; i++) 
    {  
        temp = arr[i];  
        j = i - 1;  

        while (j >= 0 && arr[j] > temp) 
        {  
            arr[j + 1] = arr[j];  
            j = j - 1;  
        }  
        arr[j + 1] = temp;  
    }  
}

int main()  
{  
    int arr[] = { 1,4,2,5,333,3,5,7777,4,4,3,22,1,4,3,666,4,6,8,999,4,3,5,32 };  
    int n = sizeof(arr) / sizeof(arr[0]);  

    insertionSort(arr, n);  

    for(int i = 0; i < n; i++){
        cout << arr[i] << " ";
    }

    return 0;  
}

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Contributed on Jan 16 2021

Glamorous Gibbon

0 Answers Avg Quality 2/10

insertion sort

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def sortNumList(list1):
  x = len(list1)-1
  while True:
    index = 0
    while True:
      if list1[index] > list1[index+1]:
        get = list1[index], list1[index+1]
        list1[index+1], list1[index] = get
        # print(list1[index], list1[index+1])
        index +=1
        if index == x:
          break
          if(all(list1[i] <= list1[i + 1] for i in range(len(list1)-1))):
            break
            return list1

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Contributed on Mar 19 2022

Clean Cow

0 Answers Avg Quality 2/10

insertion sort algorithm

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// C++ program for insertion sort
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to sort an array using
// insertion sort
void insertionSort(int arr[], int n)
{
    int i, key, j;
    for (i = 1; i < n; i++)
    {
        key = arr[i];
        j = i - 1;
 
        // Move elements of arr[0..i-1], 
        // that are greater than key, to one
        // position ahead of their
        // current position
        while (j >= 0 && arr[j] > key)
        {
            arr[j + 1] = arr[j];
            j = j - 1;
        }
        arr[j + 1] = key;
    }
}
 
// A utility function to print an array
// of size n
void printArray(int arr[], int n)
{
    int i;
    for (i = 0; i < n; i++)
        cout << arr[i] << " ";
    cout << endl;
}
 
// Driver code
int main()
{
    int arr[] = { 12, 11, 13, 5, 6 };
    int N = sizeof(arr) / sizeof(arr[0]);
 
    insertionSort(arr, N);
    printArray(arr, N);
 
    return 0;
}
// This is code is contributed by rathbhupendra

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Source: www.geeksforgeeks.org

Tags: algorithm algo

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Contributed on Apr 10 2023

Shabab Mosharraf

0 Answers Avg Quality 2/10

insertion sort

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void insertion_sort ( int A[ ] , int n) 
{
     for(int i=1; i<n ;i++) {
      /*storing current element whose left side is checked for its correct position .*/
	  int temp = A[i];    
      int j = i-1;

      /* check whether the adjacent element in left side is greater or less than the current element. */
       while( j >= 0 && A[j] > temp) {
       // moving the left side element to one position forward.
            A[j+1] = A[j];   
            j--;
       }
       // moving current element to its  correct position.
       A[j+1] = temp;       
     }  
}

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Source: Grepper

Tags: c++

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Contributed on Jun 14 2022

Lavish Garg

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insertion sort

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Void insertionSort(int arr[ ], int n){
               Int i, temp, j;
               For(i=1; i<n; i++){   //We will start iterating through index 1
                     temp=arr[ i ];         //Will store the value in a temporary variable
                      J= i-1;
                      While(j>=0 and arr[ j ] > temp){    //check the which value is greater
                                 arr[ j+1] = arr[ j ];
                                 j - -;
                       }
                    arr[ j+1 ] = temp;   //Replace that value with the temporary variable
               }
}

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Source: www.codingninjas.com

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Contributed on Aug 25 2022

M. Haris Imran

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insertion sort

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 function insertionSortRicorsivo(array A, int n)
     if n>1
        insertionSortRicorsivo(A,n-1)
        value ← A[n-1]
        j ← n-2
        while j >= 0 and A[j] > value 
         do A[j + 1] ← A[j]
            j ← j-1
        A[j+1] ← value

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Source: it.wikipedia.org

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Contributed on Apr 04 2021

Phil the ice cream man

0 Answers Avg Quality 2/10

Insertion sort

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public int[] insertionSort(int[] arr)
      for (j = 1; j < arr.length; j++) {
         int key = arr[j]
         int i = j - 1
         while (i > 0 and arr[i] > key) {
            arr[i+1] = arr[i]
            i -= 1
         }
         arr[i+1] = key
      }
      return arr;

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Source: www.freecodecamp.org

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Contributed on May 07 2022

Wrong Worm

0 Answers Avg Quality 2/10

insertion sort

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insertion sort

void insertion_sort ( int A[ ] , int n) 
{
     for( int i = 0 ;i < n ; i++ ) {
    /*storing current element whose left side is checked for its 
             correct position .*/

      int temp = A[ i ];    
      int j = i;

       /* check whether the adjacent element in left side is greater or
            less than the current element. */

          while(  j > 0  && temp < A[ j -1]) {

           // moving the left side element to one position forward.
                A[ j ] = A[ j-1];   
                j= j - 1;

           }
         // moving current element to its  correct position.
           A[ j ] = temp;       
     }  
}

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Source: www.hackerearth.com

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Contributed on May 25 2023

Encouraging Earthworm

0 Answers Avg Quality 2/10

insertion sort algorithm in descending order

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