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python dictionary key

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YOU.com answered on November 27, 2019 Popularity 9/10 Helpfulness 1/10

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# Creating a sample dictionary
person = {
    'name': 'John',
    'age': 30,
    'gender': 'Male'
}

# Accessing dictionary keys
keys = person.keys()

# Printing the keys
print(keys)

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Contributed on Sep 12 2023

YOU.com

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python dictionary

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215

#Creating dictionaries
dict1 = {'color': 'blue', 'shape': 'square', 'volume':40}
dict2 = {'color': 'red', 'edges': 4, 'perimeter':15}

#Creating new pairs and updating old ones
dict1['area'] = 25 #{'color': 'blue', 'shape': 'square', 'volume': 40, 'area': 25}
dict2['perimeter'] = 20 #{'color': 'red', 'edges': 4, 'perimeter': 20}

#Accessing values through keys
print(dict1['shape'])

#You can also use get, which doesn't cause an exception when the key is not found
dict1.get('false_key') #returns None
dict1.get('false_key', "key not found") #returns the custom message that you wrote 

#Deleting pairs
dict1.pop('volume')

#Merging two dictionaries
dict1.update(dict2) #if a key exists in both, it takes the value of the second dict
dict1 #{'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20}

#Getting only the values, keys or both (can be used in loops)
dict1.values() #dict_values(['red', 'square', 25, 4, 20])
dict1.keys() #dict_keys(['color', 'shape', 'area', 'edges', 'perimeter'])
dict1.items() 
#dict_items([('color', 'red'), ('shape', 'square'), ('area', 25), ('edges', 4), ('perimeter', 20)])

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Contributed on May 20 2020

MitroGr

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keys python dictionary

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# Dictionary with three keys
Dictionary1 = {'A': 'Geeks', 'B': 'For', 'C': 'Geeks'}
 
# Printing keys of dictionary
print(Dictionary1.keys())

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Source: www.geeksforgeeks.org

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Contributed on Feb 03 2023

Comfortable Cow

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python dictionary

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#title			:Dictionary Example
#author         :Josh Cogburn
#date           :20191127
#github         :https://github.com/josh-cogburn
#====================================================

thisdict = {
	"brand": "Ford",
 	"model": "Mustang",
 	"year": 1964
}

#Assigning a value
thisdict["year"] = 2018

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Contributed on Nov 27 2019

Different Dotterel

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dictionary keys python

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some_dict.keys()

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Contributed on Oct 29 2023

Innocent Iguana

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dictionary python

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# dictionary refresh


new_dict = {
    "first":"1,2,3",
    "second":"321",
    "third":"000",
}


# adding to dictionary
new_dict.update({"fourth":"D"})
print(new_dict)

#removing from dictionary
new_dict.pop("first")
print(new_dict)


new = {"five":"888"}
#updating a dictionary
new_dict.update(new)
print(new_dict)

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Contributed on Oct 26 2022

An7wan

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python dictionary

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human = {
  "code": "Python",
  "name": "John",
  "age": 32
}

print(human["age"])
#32 :D

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Contributed on May 22 2022

Msk SK

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dictionary python

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dictionary = {
    "name": "Elie",
    "family name": "Carcassonne",
    "date of born": "01/01/2001",
    "list": ["hey", "hey"]
}

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Source: openclassrooms.com

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Contributed on Nov 10 2021

moi_crn

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python dictionary

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l = {"a":"aaaaa"}
print(l["a"])
#aaaa

l = [{"a":"aaaaa"}, {"a":"AAA65675765"}]
print(l[0]["a"])
#aaaa

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Contributed on Aug 03 2022

Javasper

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python dictionary

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# Creating an empty Dictionary
Dict = {}
print("Empty Dictionary: ")
print(Dict)
 
# Creating a Dictionary
# with dict() method
Dict = dict({1: 'Geeks', 2: 'For', 3:'Geeks'})
print("\nDictionary with the use of dict(): ")
print(Dict)
 
# Creating a Dictionary
# with each item as a Pair
Dict = dict([(1, 'Geeks'), (2, 'For')])
print("\nDictionary with each item as a pair: ")
print(Dict)

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Source: www.geeksforgeeks.org

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Contributed on Apr 16 2022

Repulsive Rhinoceros

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python dictionary

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<view> = <dict>.keys()                          # Coll. of keys that reflects changes.
<view> = <dict>.values()                        # Coll. of values that reflects changes.
<view> = <dict>.items()                         # Coll. of key-value tuples that reflects chgs.
value  = <dict>.get(key, default=None)          # Returns default if key is missing.
value  = <dict>.setdefault(key, default=None)   # Returns and writes default if key is missing.
<dict> = collections.defaultdict(<type>)        # Creates a dict with default value of type.
<dict> = collections.defaultdict(lambda: 1)     # Creates a dict with default value 1.
<dict> = dict(<collection>)                     # Creates a dict from coll. of key-value pairs.
<dict> = dict(zip(keys, values))                # Creates a dict from two collections.
<dict> = dict.fromkeys(keys [, value])          # Creates a dict from collection of keys.
<dict>.update(<dict>)                           # Adds items. Replaces ones with matching keys.
value = <dict>.pop(key)                         # Removes item or raises KeyError.
{k for k, v in <dict>.items() if v == value}    # Returns set of keys that point to the value.
{k: v for k, v in <dict>.items() if k in keys}  # Returns a dictionary, filtered by keys.

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Source: gto76.github.io

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Contributed on Mar 10 2022

Michael

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